How likely is it that for breaking 2048 bit RSA integers you'll just need 2048 unnoisy qbits?
That this lowered 20M requirement is just ploy to keep people using 2048 bits, not 4K as required by GNU. It is my understanding that 2048 qbits are already in reach to well-funded state agencies.
That this lowered 20M requirement is just ploy to keep people using 2048 bits, not 4K as required by GNU. It is my understanding that 2048 qbits are already in reach to well-funded state agencies.