> But the atmosphere is thinner, so this makes it harder to
> hear? Or quieter?
Sound intensity for a plane wave is given by the equation $I = \xi^2 \omega^2 c \rho$. Here $\xi$ is the particle displacement (the amplitude of our wave), $\omega$ is the angular frequency, and $c \rho$, typically called $Z$, is the characteristic acoustic impedance, where $c$ is the speed of sound and $\rho$ is the density of the medium.
Given that the speed of sound is roughly independent of pressure, and keeping all other variables equal, as $\rho$ decreases, $I$ also decreases. So yes, on Mars, sounds are much quieter.
I knew my bait would bring someone smarter than me out of the woodwork! Thanks, very informative. Can I ask what's your background that led you to this?
Considering the propensity for dust storms I'm going to say windy. But the atmosphere is thinner, so this makes it harder to hear? Or quieter?